(3x-1)*(2x^2+4x+3)=

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Solution for (3x-1)*(2x^2+4x+3)= equation: 


Simplifying
(3x + -1)(2x2 + 4x + 3) = 0

Reorder the terms:
(-1 + 3x)(2x2 + 4x + 3) = 0

Reorder the terms:
(-1 + 3x)(3 + 4x + 2x2) = 0

Multiply (-1 + 3x) * (3 + 4x + 2x2)
(-1(3 + 4x + 2x2) + 3x * (3 + 4x + 2x2)) = 0
((3 * -1 + 4x * -1 + 2x2 * -1) + 3x * (3 + 4x + 2x2)) = 0
((-3 + -4x + -2x2) + 3x * (3 + 4x + 2x2)) = 0
(-3 + -4x + -2x2 + (3 * 3x + 4x * 3x + 2x2 * 3x)) = 0
(-3 + -4x + -2x2 + (9x + 12x2 + 6x3)) = 0

Reorder the terms:
(-3 + -4x + 9x + -2x2 + 12x2 + 6x3) = 0

Combine like terms: -4x + 9x = 5x
(-3 + 5x + -2x2 + 12x2 + 6x3) = 0

Combine like terms: -2x2 + 12x2 = 10x2
(-3 + 5x + 10x2 + 6x3) = 0

Solving
-3 + 5x + 10x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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